Consider the lines

$l_1$:$,x=1+2t,y=1-t,z=3t,$tinR

$l_2$:$,\frac{x-1}{2}=\frac{y+2}{-1}=z-5$

the plane

$II$ : $,x+2y+3z+3=0,$

and the point $P(1,0,2).$

$($b$)$ Either find an equation of the plane which is perpendicular to the plane $$ and passes through the points $P$ and $Q,$ or explain why such a plane does not exist.