Consider the logic statement: $(($NOT x$)$ OR y$)$ AND z where $x,y,$ and $z$ can be true or false $(1$ or $0).$ Which of the following combinations are correct?

Hint: first write out your truth table just as we did in the theory lecture.

If $x$ and $z$ are false, but $y$ is true, the statement is false

If $x$ is true, the statement is always true.

If $y$ is true, the statement is always true.

If $x$ and $y$ are true, but $z$ is false, the statement is false.

If $z$ is false, the statement is always true.

If $z$ is false the statement is always false

If all three are true the entire statement is false