Question: Consider the same equations of motion as in Problem 1 but under a forced vibration: 01 () [16 -81 [2]+[% 78) = {2cos(4t)}, Lo

Consider the same equations of motion as in Problem 1 but under a forced vibration: 01 () [16 -81 [2]+[78] =

Consider the same equations of motion as in Problem 1 but under a forced vibration: 01 () [16 -81 [2]+[% 78) = {2cos(4t)}, Lo 21 16x with the same initial conditions: -8 Follow the 6 steps described in Modal Analysis in Part I to answer the following questions. (The natural frequencies and vibration modes are the same as calculated in Problem 1.) (0)=0} {*}-{} = Transform the force term {2cos(4t)} into the generalized f JQ(t)) force: (Q (t)) = (a) What is the value of B? (b) What is the value of C? (c) What is the value of D? The generalized coordinates q (t) and q (t) has the following solution: 9 (t) = C cos(2t) + 0.5 sin(2t) + D cos(4t) 92 (t) = E cos(12t) + F sin(12t) +0.25 cos(4t) (d) What is the value of E? (e) What is the value of F? (A cos(4t)) (B cos(4t)) The total solution can be expressed as: x (t) = 0.5417 cos(2t) + H sin(2t) + 0.625 cos (12t) - 0.1443 sin(12t) -0.1667 cos(4t) x (t) = 0.5417 cos(2t) + 0.25 sin(2t) - 0.625 cos(12t) + 0.1443 sin(12t) + G cos(4t) (f) What is the value of H? (g) What is the value of G?

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