Consider the set A = {0,1,0,9}, and let R be a binary relation from A to A which is both an quivalence relation and a function. A. There are no binary relations from A into A which are simultaneously equivalence relations and functions. That is, R does not exist. B. If R is an equivalence relation, then Ris, in particular, symmetric. Therefore, R must contain pairs whose components are different. OC. The binary relation {(0,0),(1,1),(0,4),(0,0)} is a subset of R. OD. R is a subset of the binary relation {(0,0),(1,1),(0,1),(0,0)}