Consider the spaceship on a long trip with a constant acceleration of 1g . Although the derivation is beyond the scope of this book, it is possible to show that, as long as the ship is gone from Earth for many years, the amount of time that passes on the spaceship during the trip is approximately: tship=2cgln(gDc2) In this formula, D is the distance to the destination and ln stands for the natural logarithm. (Your calculator probably has a key for taking natural logarithms [usually labeled "ln"], so you can use this formula even if you are not familiar with them.) If D is in meters, g = 9.8m/s2 , and c = 3 108 m/s , the answer will be in units of seconds. Part A How much time will pass on the ship during its trip to a star that is 500 light-years away? Express your answer in years to two significant figures. View Available Hint(s)for Part A Activate to select the appropriates template from the following choices. Operate up and down arrow for selection and press enter to choose the input value typeActivate to select the appropriates symbol from the following choices. Operate up and down arrow for selection and press enter to choose the input value type tship = yr Part B Compare your answer to the amount of time that passes on Earth. Express your answer using two significant figures. View Available Hint(s)for Part B Activate to select the appropriates template from the following choices. Operate up and down arrow for selection and press enter to choose the input value