Question: Consider the triangle with vertices (-1,0),(1,0), and (0,1) and the parabola y =-x2+1. Use Archimedes propositions and some calculus to show that in the area

Consider the triangle with vertices (-1,0),(1,0), and (0,1) and the parabola y =-x2+1. Use Archimedes propositions and some calculus to show that in the area of the given triangle is 3/4 of the area between the given parabola and the x-axis

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