Consider the two statements

$1.($p $->$ q$)^($p $->-$q$)$

$2.($p $->$ q$)^(-$p $->$ q$).$

$$ Neither is a contradiction.

O $1.$ is a contradiction, $2.$ is not.

O $2.$ is a contradiction, $1.$ is not.

$$ They are both contradictions.