Question: Consider this algorithm: procedure mi(a, n) if (n e) then return (1) 1) then return (a) m = floor(n/2) X = m1(a,m) X = X*

Consider this algorithm: procedure mi(a, n) if (n e) then return (1) 1) then return (a) m = floor(n/2) X = m1(a,m) X = X* X if(n is even) return (x) return (a * x) The height of its recurrence tree is The computational complexity of the algorithm is of

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