Consider this code:

class A$\{$

public A$()\{\}$

public void f$()\{$

System.out.println$("$in A$\text{'}$s f$")$;

return;$\}$

public void h$($int i$)\{$

System.out.println$("$in A$\text{'}$s h$,$ i$="+$ i$)$;

return;$\}$

public void s$($double d$)\{$

System.out.println$("$in A$\text{'}$s s$,$ d$="+$ d$)$;

return;$\}$

class B extends A$\{$

public B$()\{\}$

public void f$()\{$

System.out.println$("$in B$\text{'}$s f$")$;

return;$\}$

public void h$($int i$)\{$

System.out.println$("$in B$\text{'}$s h$,$ i$="+$ i$)$;

return;$\}$

public void s$($int j$)\{$

System.out.println$("$in B$\text{'}$s s$,$ j$="+$ j$)$;

return;$\}$

$\}$

class C extends A$\{$

public C$()\{\}$

public void f$()$

$\{$

System.out.println$("$in C$\text{'}$s f$")$;

return

$\}$

$\}$

The following code is in the main method:

$A$ a$1=$ new $B()$;

$A$ a$2=$ new $C()$;

B b $=$ new $)$;

A a $=$ new $A()$;

From the following select all correct answers $($yes$,$ there is more than one correct answer$)$

Select one or more:

a$.$ The line a$.)$ calls method $f$ defined in $A$

b$.$ The line a$2.)$ calls the method $f$ defined in $B$

c$.$ The line $a2.h(1)$ calls method $h$ defined in $B$

d$.$ The line a$2.h(1)$ calls method $h$ defined in $A$