Consider this fourth order linear differential equation. Solve the initial value problem and enter the solution as a function of $t.$

$y^{(4)}+29y^{\text{'}\text{'}}+100y=0$

$y(0)=2,y^{\text{'}}(0)=9,y^{\text{'}\text{'}}(0)=-71,y^{\text{'}\text{'}\text{'}}(0)=-141$

$[$Hint: the charateristic polynomial can be factored using a quadratic technique.$]$

$y^{\text{'}}(t)=$