Consider trying to solve Best Vertex Cover using hill climbing in the following state space. State:...

  

Transcribed Image Text:

Consider trying to solve Best Vertex Cover using hill climbing in the following state space. State: Any set of vertices. Neighbors of state S: Either add one vertex to S or delete one vertex from S. Error function: Max (0,T-(Total value of the vertices in S)) + sum of the cost of all edges that connect two vertices in S where the cost of an edge is considered to be the value of its lower end. For example, in graph 1, suppose S= { A,C } and T = 16. Edge A - C is in G, value(A)=3, value(C)=6, so cost(A-C)=3. So Error(S) = Max(0,(16—9))+3 = 10. What is the sequence of states encountered doing simple hill-climbing in this space, to solve this problem for Graph 2, starting from state {F,G,H,I,J } with a target of T = 20? Consider trying to solve Best Vertex Cover using hill climbing in the following state space. State: Any set of vertices. Neighbors of state S: Either add one vertex to S or delete one vertex from S. Error function: Max (0,T-(Total value of the vertices in S)) + sum of the cost of all edges that connect two vertices in S where the cost of an edge is considered to be the value of its lower end. For example, in graph 1, suppose S= { A,C } and T = 16. Edge A - C is in G, value(A)=3, value(C)=6, so cost(A-C)=3. So Error(S) = Max(0,(16—9))+3 = 10. What is the sequence of states encountered doing simple hill-climbing in this space, to solve this problem for Graph 2, starting from state {F,G,H,I,J } with a target of T = 20?

Answer rating: 100% (QA)

To solve the Best Vertex Cover problem using simple hill climbing in the given state space we can ... View the full answer