Consider two hosts, A and B$,$ connected by a single link of rate R bps$.$

Suppose that the two hosts are separated by m meters, and suppose the

propagation speed along the link is s meters$/$sec$.$ Host A is to send a

packet of size L bits to Host B$.$

a$.$ Ignoring processing and queuing delay, obtain an expression for the

end$-$to$-$end delay.

b$.$ Suppose s$=2\mathrm{.}5*108$ meters$/$sec$,$ L$=120$ bits, and R$=56$kbps$.$ Find the

distance m so that the propagation delay equals transmission delay