Question: Consider two point charges 91 = 6nC and 92 = 4nC positioned at x = (51 - 79k)cm and x2 = (2 + 3

Consider two point charges 91 = 6nC and 92 = 4nC positioned

Consider two point charges 91 = 6nC and 92 = 4nC positioned at x = (51 - 79k)cm and x2 = (2 + 3 7)cm, respectively. = (a) Express the electrostatic force acting on particle 1 in the form F1 F() + F() } + F() k and the electrostatic force on particle 2 in the form F2 = (F() + F() + F) ) with numerical values for all six components in SI units. (b) Relocate particle 1 to the position x = (x y + z ) such that it experiences the force F = (5 + 7 +8) 106N. Find the three coordinates x1, 31, in units of cm.

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a Given q1 6nC 6 x 109 C q2 4nC 4 x 109 C x1 5i 7j 9k cm x2 21i 3j 7k cm The electrostatic force bet... View full answer

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