Consider two points in an electric field. The potential at point $1,v_1,$ is $45$ V $.$ The potential at point $2,V_2,$ is $196$ V $.$ An electron at rest at point $1$ is accelerated by the electric field to point $2.$

Part $($a$)$

Write an equation for the change of electric potential energy $U$ of the electron in terms of the symbols given.

$U=$

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Part $($b$)v$

Find the numerical value of the change of the electric potential energy in electron volts $($ eV $).$

$U=-151$

$U=-151\mathrm{.}0$

$$ Correct!

Part $($c$)$

Express $v_2,$ the speed of the electron at point $2,$ in terms of $U,$ and the mass of the electron $m_e.$

$v_2=\sqrt[\phantom{2}]{2}\frac{U}{m_e}$

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Part $($d$)V$

Find the numerical value of $v_2$ in $\frac{m}{s}.$

$v_2=7\mathrm{.}29({10}^6)$

$v_2=7\mathrm{.}290{10}^6$

$$ Correct!

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