Consider the stereoisomeric formulas of 1,2-cyclopentanediol. At high dilutions in CCl4, both isomers have a band at 3752 cm-1. Assume the cyclopentane ring is coplanar and then draw the structures of the two isomers. Indicate which isomer, even in dilute solution, will have a band at 3372 cm-1 and explain its origin.

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Solution at frequency 3626 cma IR signal is due to free OH group ... View the full answer