Considering the following disassembly:

$($gdb$)$ disass main

Dump of assembler code for function main:

$0$x$080483$db $<+0>$: push $\%$ebp

$0$x$080483$dc $<+1>$: mov $\%$esp,$\%$ebp

$0$x$080483$de $<+3>$: sub $$0$xc$,\%$esp

$0$x$080483$e$1<+6>$: mov $0$x$8(\%$ebp$),\%$edx

$0$x$080483$e$4<+9>$: mov $0$xc$(\%$ebp$),\%$eax

$0$x$080483$e$7<+12>$: add $\%$edx,$\%$eax

$0$x$080483$e$9<+14>$: mov $\%$eax,$-0$xc$(\%$ebp$)$

$0$x$080483$ec $<+17>$: mov $-0$xc$(\%$ebp$),\%$eax

$0$x$080483$ef $<+20>$: imul $0$x$10(\%$ebp$),\%$eax

$0$x$080483$f$3<+24>$: mov $\%$eax,$-0$x$8(\%$ebp$)$

$0$x$080483$f$6<+27>$: movl $$0$x$2,-0$x$4(\%$ebp$)$

$0$x$080483$fd $<+34>$: mov $$0$x$3,\%$eax

$0$x$08048402<+39>$: leave

$0$x$08048403<+40>$: ret

How many bytes does the function main use to represent its code?