Question: Considering the following MIPS code: begin: loop: finish: addi $t0,$zero, 22 move $t1,$zero li $a0, 0 beq add addi addi j $t0, $t1, finish

Considering the following MIPS code: begin: loop: finish: addi $t0,$zero, 22 move

Considering the following MIPS code: begin: loop: finish: addi $t0,$zero, 22 move $t1,$zero li $a0, 0 beq add addi addi j $t0, $t1, finish $t1,$t1, $a0 $t0,$t0, -4 $a0, $a0, 1 loop a. Explain the meaning of each instruction by inserting (inline) comments b. Give a possible high-level pseudo-code for the above MIPS code. c. What is the value of $t0 when the program reaches "finish"? d. What is the value of $a0 when the program reaches "finish"?

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a begin addi t0 zero 22 t0 will contain value 022 22 move t1 zero move the content of register zero ... View full answer

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