Question: { const n = a . length; const b = [ ] ; for ( let i = 0 ; i < n / 2

{
const n = a.length;
const b =[];
for (let i =0; i < n /2; i++){
b.push(a[i]);
b.push(a[n - i -1]);
}
// If the input array has odd length, add the middle element to the end of the rearranged array
if (n %2!==0){
b.push(a[Math.floor(n /2)]);
}
return b;
}

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