1. Construct a word problem about the specified topic in each number. Consider the given conditions for each item. Solve it using the 5-step procedure. Take note the problem should be a population proportion problem.

Solution: STEP 1: State the null and alternative hypothesis. Ho: p = 0.10 Ha: p = 0.10 STEP 2: Choose a level of significance. a = 0.05 STEP 3: Compute the test statistic. Given: x - 125p = 0.10 n = 780 Zoom 125 0.16-0.10 780 Zcom 010 1 0.10) p = 0.16 Zcom 0.06 0.03 Zcom = 5.59 STEP 4: Determine the critical value. Since the alternative hypothesis is non-directional, the two-tailed test shall be used. Divide a by 2 which will represent the shaded region. Using the Area Under the Normal Curve Table, critical values at 0.05 level of significance for two-tailed test are + 1.96. a/2 - 0.025 a/2 - 0.025 Non-rejection Region -1.96 0 1.96 Rejection Region Rejection Region STEP 5: Make a decision whether to reject or fail to reject the null hypothesis. Draw a conclusion. DECISION: Since the computed test statistic Zoom - 5.59 is greater than the critical value or it falls in the rejection region, reject the null hypothesis. CONCLUSION: Therefore, we conclude that at 0.05 level of significance, there is enough evidence that the percentage of Grade 7 students who are underweight is different from 10%.Using the given set of valueslparts of the test of hypothesis involving population proportions, construct your own word problem about the specified topic in each number and solve it using the 5step procedure. 1. Topic: Numeracy rate at a certain high school a = 0.05 Ho: p = 0.6 Ha: p at 0.6 2 Topic: Spread 0t vimslboctorlo Population proportion is 0.85. Non-directional test