Question: Construct an equivalent Truth table using only OR and NOT. Here is my code: def OR(a, b): if a == 1 or b ==1: return
Construct an equivalent Truth table using only OR and NOT.
Here is my code:
def OR(a, b): if a == 1 or b ==1: return 1 else: return 0
if __name__=='__main__': print(" Truth table for OR gate") print(" A = 0, B = 0 : A OR B =",OR(0,0)) print(" A = 0, B = 1 : A OR B =",OR(0,1)) print(" A = 1, B = 0 : A OR B =",OR(1,0)) print(" A = 1, B = 1 : A OR B =",OR(1,1))
def NOT(a): return not a
if __name__=='__main__': print(" NOT gate Truth Table ") print(" A = False : NOT A =",NOT(0)) print(" A = True : NOT A =",NOT(1))
I keep getting this error:
else: ^ SyntaxError: invalid syntax
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