Question: content area top Part 1 A baseball diamond is a square 90 ft on a side. A player runs from first base to second at

content area top Part 1 A baseball diamond is a square 90 ft on a side. A player runs from first base to second at a rate of 16 ft/sec. 60 prime x y x y a. At what rate is the player's distance from third base changing when the player is 60 ft from first base? b. At what rates are angles theta 1 and theta 2 (see the figure) changing at that time? c. The player slides into second base at the rate of 15 ft divided by sec. At what rates are angles theta 1 and theta 2changing as the player touches base? Question content area bottom Part 1 a. The rate is negative StartFraction 16 Over StartRoot 10 EndRoot EndFraction ft/sec. (Type an exact answer, using radicals as needed.) Part 2 b. When the player is 60 prime from first base, what are the rates of change of the angles theta 1 and theta 2? StartFraction 4 Over 25 EndFraction,negative StartFraction 4 Over 25 EndFraction rad/sec (Simplify your answers. Use a comma to separate answers as needed.) Part 3 c. As the player slides into second base at a rate of 15 ft divided by sec, what are the rates of change of the angles theta 1 and theta 2? enter your response here rad/sec (Simplify your answers. Use a comma to separate answers as needed.)

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