Question: Continuous Probability Distribution The time required to assemble an electronic component is normally distributed, with a mean of 12 minutes and a standard deviation of

Continuous Probability Distribution

The time required to assemble an electronic component is normally distributed, with a mean of 12 minutes and a standard deviation of 1.5 minutes. Find the probability that a particular assembly take more than 14 minutes.

a.0.9082

b.0.0918

c.0.8164

d.0.4541

Continuous Probability Distribution

The time required to assemble an electronic component is normally distributed, with a mean of 12 minutes and a standard deviation of 1.5 minutes. Find the probability that a particular assembly take less than 14 minutes.

a.0.9082

b.0.0918

c.0.8164

d.0.4541

Continuous Probability Distribution

The time required to assemble an electronic component is normally distributed, with a mean of 12 minutes and a standard deviation of 1.5 minutes. Find the probability that a particular assembly take less than 10 minutes.

a.0.9082

b.0.0918

c.0.8164

d.0.4541

Continuous Probability Distribution

The time required to assemble an electronic component is normally distributed, with a mean of 12 minutes and a standard deviation of 1.5 minutes. Find the probability that a particular assembly take more than 10 minutes.

a.0.9082

b.0.0918

c.0.8164

d.0.4541

Probability distributions

For a discrete probability distribution to be valid

a.the probabilities must lie between0and1 (inclusive)

b.the sum of all probabilities must be1

c.all the other choices are correct

d.the probabilities should be non-negative

Probability distributions

The probability distribution forX, daily demand of a particular newspaper at a local newsagency(in hundreds) is as follows:

x

1

2

3

4

p(x)

0.05

0.42

0.44

0.09

Calculate the expected value and the variance.

a.E(X) =2.57 (in hundreds of newspapers),V(X)= 0.525 (in hundreds of newspapers)2

b.E(X)=2.57 (in hundreds of newspapers),V(X)=0.525(in hundreds of newspapers)

c.E(X)=2.57 (in hundreds of newspapers)2,V(X)=0.525(in hundreds of newspapers)

d.E(X)=2.57 (in hundreds of newspapers)2,V(X)=0.525(in hundreds of newspapers)2

Probability distributions

Indicate whether the following variable is discrete or continuous: The weights of new members at a gymnasium

a.Discrete

b.Continuous

c.Discrete or continuous

d.All the above choices are correct

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