Question: Conventional equilibrium considerations do not apply when a reaction is driven by light absorption and the steadystate concentration of products and reactants might differ significantly

Conventional equilibrium considerations do not apply when a reaction is driven by light absorption and the steadystate concentration of products and reactants might differ significantly from equilibrium values For instance suppose the reaction A B is driven by light absorption and that its rate is Ia but that the reverse reaction B A is bimolecular and second order with a rate krB2 What is the stationary state concentration of B Why does this photostationary state differ from the equilibrium state

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