Convert $1\mathrm{.}23{10}^{-8}c{m}^3$ into $i{n}^3.($answer is $7\mathrm{.}51{10}^{-10}i{n}^3)$

The first dimension conversion factor is $2\mathrm{.}54cm=1in,$ then cube both sides to get the cubed conversion.

Fill in $4$ blanks.

$(2\mathrm{.}54cm{)}^3=(1in{)}^3$

$=1i{n}^3$

$(-----------------------)=7\mathrm{.}51{10}^{-10}i{n}^3$

a$.1i{n}^3$

b$.2\mathrm{.}54c{m}^3$

c$.16\mathrm{.}3871c{m}^3$

d$.1$ in

e$.2\mathrm{.}54cm$

f$.{10}^{9}m$

g$.{10}^{-9}m$

h$.1\mathrm{.}23{10}^{-8}cm$

i$.1\mathrm{.}23{10}^{-2}cm$

j$.2\mathrm{.}02{10}^{-7}c{m}^3$

k$.1\mathrm{.}23{10}^{-8}c{m}^3$