Question: Convert the following C code to floating point MIPS Code: Consider A is in $s0, B and C are in $f1 and $f2, base address

Convert the following C code to floating point MIPS Code:

Consider A is in $s0, B and C are in $f1 and $f2, base address of float array D is in $s1.

(float)B = 20*A + (float)C+8

A = (float)C - (float)B

D[5] = A

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