Convert the following triple integral into cylindrical coordinates ${\displaystyle \underset{-2}{\overset{2}{}}}{\displaystyle \underset{-\sqrt[\phantom{2}]{4-x^2}}{\overset{0}{}}}{\displaystyle \underset{4(x^2+y^2)}{\overset{16}{}}}{x}^{2}dzdydx$

a$.{\displaystyle \underset{0}{\overset{}{}}}{\displaystyle \underset{4}{\overset{0}{}}}{\displaystyle \underset{4r}{\overset{16-r^2}{}}}{r}^{2}cosdzdrd$

b$.{\displaystyle \underset{}{\overset{2}{}}}{\displaystyle \underset{0}{\overset{2}{}}}{\displaystyle \underset{4r^2}{\overset{16}{}}}{r}^{3}co{s}^{2}dzdrd$

c$.{\displaystyle \underset{0}{\overset{}{}}}{\displaystyle \underset{0}{\overset{2}{}}}{\displaystyle \underset{4r^2}{\overset{16}{}}}{r}^{2}co{s}^{2}dzdrd$

d$.{\displaystyle \underset{}{\overset{2}{}}}{\displaystyle \underset{0}{\overset{4}{}}}{\displaystyle \underset{4r^2}{\overset{16}{}}}{r}^{3}co{s}^{2}dzdrd$