Convert the given integral into an integral in spherical coordinates.

${\displaystyle \underset{-2}{\overset{2}{}}}{\displaystyle \underset{0}{\overset{\sqrt[\phantom{2}]{4-x^2}}{}}}{\displaystyle \underset{-\sqrt[\phantom{2}]{4-x^2}-y^2}{\overset{\sqrt[\phantom{2}]{4-x^2}\frac{-}{b}ar(y{)}^2}{}}}(x^2{y}^2{z}^2{)}^{2}dzdydx$

${\displaystyle \underset{0}{\overset{(2x{)}^{}}{}}}{\displaystyle \underset{0}{\overset{(2x)}{}}}{\displaystyle \underset{0}{\overset{2}{}}}()ddd$