Convert the nfa defined by

$(q_0,a)=\{q_0,q_1\}$

$(q_1,b)=\{q_1,q_2\}$

$(q_2,a)=\{q_2\}$

with initial state $q_0$ and final state $q_2$ into an equivalent dfa.

Convert the nfa defined by

$(q_0,a)=\{q_0,q_1\}$

$(q_1,b)=\{q_1,q_2\}$

$(q_2,a)=\{q_2\}$

$(q_0,)=\{q_2\}$

with initial state $q_0$ and final state $q_2$ into an equivalent dfa.

Convert the nfa defined by

$(q_0,a)=\{q_0,q_1\}$

$(q_1,b)=\{q_1,q_2\}$

$(q_2,a)=\{q_2\}$

$(q_1,)=\{q_1,q_2\}$

with initial state $q_0$ and final state $q_2$ into an equivalent dfa.

Please do $3$ and $5$ and explain to me how to do it$.$ Thank you!