Convert the nfa defined by

$(q_0,a)=\{q_0,q_1\}$

$(q_1,b)=\{q_1,q_2\}$

$(q_2,a)=\{q_2\}$

$(q_1,)=\{q_1,q_2\}$

with initial state $q_0$ and final state $q_2$ into an equivalent dfa.