Convert the SQL Statements into relational algebraic statements. The following operators must be used.

Unary . . (Sigma) - Selection at (Pi) Project P (Ro) - Rename Binary . U-Union n - Intersect - (Minus) - Set Difference X (Times) Product (Bowtie) Join = (Division) - Division . Student(snum: integer, sname: string, major: string, level: string, age: integer) Class( name: string, meets_at: time, room: string, fid: integer) Enrolled(snum: integer, cname: string) Faculty (fid: integer, fnarne: string, deptid: integer) The meaning of these relations is straightforward; for example, Enrolled has one record per student-class pair such that the student is enrolled in the class. 12. SELECT S.age, S.level FROM Student GROUP BY S.age, S.level, HAVING S.level IN (SELECT S1.level FROM Student S1 WHERE S1.age = S.age GROUP BY S1.level, S1.age HAVING COUNT (*) >= ALL (SELECT COUNT (*) FROM Student S2 WHERE sl.age = S2.age GROUP BY S2.level, S2.age)) 10. SELECT FROM WHERE DISTINCT S.sname Student S S.snum IN (SELECT E.snum FROM Enrolled E GROUP BY E.snum HAVING COUNT (*) >= ALL (SELECT COUNT (*) FROM Enrolled E2 GROUP BY E2.snum )) Unary . . (Sigma) - Selection at (Pi) Project P (Ro) - Rename Binary . U-Union n - Intersect - (Minus) - Set Difference X (Times) Product (Bowtie) Join = (Division) - Division . Student(snum: integer, sname: string, major: string, level: string, age: integer) Class( name: string, meets_at: time, room: string, fid: integer) Enrolled(snum: integer, cname: string) Faculty (fid: integer, fnarne: string, deptid: integer) The meaning of these relations is straightforward; for example, Enrolled has one record per student-class pair such that the student is enrolled in the class. 12. SELECT S.age, S.level FROM Student GROUP BY S.age, S.level, HAVING S.level IN (SELECT S1.level FROM Student S1 WHERE S1.age = S.age GROUP BY S1.level, S1.age HAVING COUNT (*) >= ALL (SELECT COUNT (*) FROM Student S2 WHERE sl.age = S2.age GROUP BY S2.level, S2.age)) 10. SELECT FROM WHERE DISTINCT S.sname Student S S.snum IN (SELECT E.snum FROM Enrolled E GROUP BY E.snum HAVING COUNT (*) >= ALL (SELECT COUNT (*) FROM Enrolled E2 GROUP BY E2.snum ))