Question: Convert this C++ code to MIPS assembly. Include documentation. #include using namespace std; int moveRobots(int *, int *, int, int ); int getNew(int, int); int

Convert this C++ code to MIPS assembly. Include documentation. #include using namespace std; int moveRobots(int *, int *, int, int ); int getNew(int, int); int main() { int x[4], y[4], i, j, myX = 25, myY = 25, move, status = 1; // initialize positions of four robots x[0] = 0; y[0] = 0; x[1] = 0; y[1] = 50; x[2] = 50; y[2] = 0; x[3] = 50; y[3] = 50; cout << "Your coordinates: 25 25 "; while (status == 1) { cout << "Enter move (1 for +x, -1 for -x, 2 for + y, -2 for -y):"; cin >> move; // process user's move if (move == 1) myX++; else if (move == -1) myX--; else if (move == 2) myY++; else if (move == -2) myY--; // update robot positions status = moveRobots(&x[0],&y[0],myX,myY); cout << "Your coordinates: " << myX << " " << myY << endl; for (i=0;i<4;i++) cout << "Robot at " << x[i] << " " << y[i] << endl; } cout << "AAAARRRRGHHHHH... Game over "; } int moveRobots(int *arg0, int *arg1, int arg2, int arg3) { int i, *ptrX, *ptrY, alive = 1; ptrX = arg0; ptrY = arg1; for (i=0;i<4;i++) { *ptrX = getNew(*ptrX,arg2); // update x-coordinate of robot i *ptrY = getNew(*ptrY,arg3); // update y-coordinate of robot i // check if robot caught user if ((*ptrX == arg2) && (*ptrY == arg3)) { alive = 0; break; } ptrX++; ptrY++; } return alive; } // move coordinate of robot closer to coordinate of user int getNew(int arg0, int arg1) { int temp, result; temp = arg0 - arg1; if (temp >= 10) result = arg0 - 10; else if (temp > 0) result = arg0 - 1; else if (temp == 0) result = arg0; else if (temp > -10) result = arg0 + 1; else if (temp <= -10) result = arg0 + 10; return result; } 

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