Copper contains $8{10}^{28}$ conduction electrons $\frac{?}{m^3}.$ A copper wire of cross$-$sectional area ${10}^{-8}{m}^2$ carries a current of $13$ mA $.$ The electron drift speed is approximately:

A$.{10}^{-19}\frac{m}{s}$

B$.{10}^6\frac{m}{s}$

Correct answer is D$,$ please explain

C$.1\frac{m}{s}$

D$.{10}^{-4}\frac{m}{s}$

E$.3{10}^8\frac{m}{s}$