Question: Correct answer: 0.017m/s I need detailed answer. An air bubble rises slowly through maple syrup. Three forces act on the bubble, the weight of the

Correct answer: 0.017m/s
I need detailed answer. An air bubble rises slowly through maple syrup. Three forces act on the bubble, the weight of the bubble, the buoyant force, and a drag force due to fluid friction between the bubble and syrup as the bubble forces the syrup out of the way to rise. The drag force is given Fdrag = 6vr0 where v is the velocity of the bubble and is the viscosity of the syrup. Assuming a 5 mm diameter bubble, what is the velocity of the bubble? In which direction does the drag force act? Syrup properties are:
= 1 Ns/m^2 = 1250 kg/m^3

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