Question: Could I get feed back as to how to prove that they are members of 2z? Thank you! EVALUATOR COMMENTS: ATTEMPT 2 The use of

Could I get feed back as to how to prove that they are members of 2z? Thank you!

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EVALUATOR COMMENTS: ATTEMPT 2 The use of i and w to represent matrices is suitable since these letters are not otherwise utilized. The use of m is not completely consistent throughout the aspect. It is not appropriate to claim that matrices are members of 2Z.2. Prove the additive identity property Let m E 2Z a b] m= for a, b, c, de 2Z : ne 2Z mon=m a bl + ; substitution a+0 b+0] mon= c+0 d+ol matrix addition men= b ; Additive Identity Property for 2Z min=m; substitutionA. Given that 2Z is a ring, prove that M(2Z) is also a ring, using the given definitions of the properties of a ring in the Assumptions section and the operations of matrix addition and multiplication, by doing the following: 1. Prove the closure property of addition for M(2Z). Justify your steps. 2. Prove the additive identity property for M(22). Justify your steps. Note: A complete proof must also contain a justification for the existence of the additive identity in M(ZZ).Let i and we 2Z for a, b, c, de 2Z w= _ * for l, m, n, o E 2Z itw E 2Z itw= a + m ; substitution C HW= atl b+m] ctn dtol ; matrix addition itl. bum. cto. do e 2% closed by property of addition. itw E 2Z by definition of M(27)EVALUATOR COMMENTS: ATTEMPT 2 Approaching Competence The proof of the additive identity property for M(2Z) is not correct, or the justification inaccurately uses or does not use the appropriate given definitions of the properties of a ring or The additive identity property for 2Z is accurately referenced to support the key step of the proof. It is not the operations of matrix addition or multiplication. accurate to claim that matrices are members of 2Z. Support for why the zero matrix is a member of M(2Z) is not established

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