Could I get this back quick, Please?

Use a dictionary to count the frequency of numbers in the given text string. Only numbers should be counted. Do not count blank spaces, letters, or punctuation. Complete the function so that input like "1001000111101" will return a dictionary that holds the count of each number that occurs in the string {'1': 7, '0': 6}. This function should:

accept a string text variable through the functions parameters;

initialize an new dictionary;

iterate over each text character to check if the character is a number

count the frequency of numbers in the input string, ignoring all other characters;

populate the new dictionary with the numbers as keys, ensuring each key is unique, and assign the value for each key with the count of that number;

return the new dictionary.

def count_numbers(text):

# Initialize a new dictionary.

dictionary = ___

# Complete the for loop to iterate through each "text" character.

for ___

# Complete the if-statement using a string method to check if the

# character is a number.

if___:

# Complete the if-statement using a logical operator to check if

# the number is not already in the dictionary.

if ___:

# Use a dictionary operation to add the number as a key

# and set the initial count value to zero.

___

# Use a dictionary operation to increment the number count value

# for the existing key.

___

return dictionary

print(count_numbers("1001000111101"))

# Should be {'1': 7, '0': 6}

print(count_numbers("Math is fun! 2+2=4"))

# Should be {'2': 2, '4': 1}

print(count_numbers("This is a sentence."))

# Should be {}

print(count_numbers("55 North Center Drive"))

# Should be {'5': 2}