Question: could i have help with 9 and 10 9 . The center of a circle is the point (x, -4). If the point (3, -1)

could i have help with 9 and 10

9 . The center of a circle is the point (x, -4). If the point (3, -1) is on the circle and the radius is v34, what is the equation of the circle in the form x2 +y2 + ax + by + c= 0? In exercises 10 and 1 1, an equation of a line and a circle are given. Find the point(s), if they exist, at which the two graphs intersect each other. Graph each on a graphing calculator and confirm your algebraically found answer. 10.) x+y =23 12+ 1= = 289 11. x-y=3 x+y - 10x+ 4y+13 =0

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