Could someone explain how to get A.rowptr and total storage?

T10-HW10.6. Representing a Sparse Matrix in CSR Format Consider the following matrix: A= T0.00 5.50 0.00 5.10 0.00 0.007 0.00 0.00 4.20 0.00 0.00 0.00 0.00 0.00 0.00 0.00 0.00 8.30 0.00 0.00 0.00 0.00 8.50 0.00 0.00 0.00 0.00 0.00 0.00 0.00 5.60 0.00 0.00 0.00 0.00 4.80 Fill in the entries to show how A is represented in CSR format (more information about csr storage using scipy sparse library) 5.5 5.1 4.2 8.3 8.5 5.6 A.data = ? 100% 3 2 5 4 0 A.col = ? 100% 0 0 1 2 3 5 A.rowptr = ? x 0% Given that data is stored as an array of 64-bit floats, and row and column indices and are stored as arrays of 32-bit integers, how many bytes in total are stored? Total Storage = 108 bytes X 0% Try a new variant Correct answer A.data = [5.5 5.1 4.2 8.3 8.5 5.6 4.8] A.col = [1 3 2 5 4 0 51 A.rowptr = [O 2 3 4 5 5 7] Total Storage = 112 bytes