could someone help me solve this?In this problem, a sample solution has been written to the given problem. However, mistakes havebeen made with those solutions.Identify where the mistakes have been made, explain what the student did wrong, and correct thesolution.a. Calculate 1x2dxSolution: Since 1xdx=ln|x|+C, then1x2dx=ln|x2|+CBecause x2is always greater than or equal to0,we can drop the absolute value symbols.Therefore1x2dx=ln(x2)+C=2ln(x)+CDescribe the mistakes. Explain your thinking fully and show your work to provide corrections tothe mistakes.b. Calculate 082xx2+12dxSolution: We start with au-substitution where u=x2+1. Then du=2xdxor12du=xdx. Thenwhen we make the substitution, we have082xx2+12dx=082u2*12du,=12082u12du,=12*23u32|082==13(82)32-13(0)32=13(8)34