Could you explain and solve how to do these problems?

Suppose u and v are functions of x that are differentiable at x=1, and that X=1. Product u(1) = 6, u'(1) = -3, v(1) = 0, v'(1) = 4. Find the values of the following derivatives at rule : f ( x ) gi ( x ) + f' (x ) g(x) (3 points) d a. (uv) dx ( 6)( 4 ) + (- 3 10 ) 4 + 0 = 4 d f(x ) dx = 424 d V b. = 40 ( 4) - (0) (- 3) quotient rule: 9( x )f'(x )- f( x ) dx u 4- 0 ( 6) 2 4 3 12 u 3 C. dx f (5 u + 30 - 5)= (f. q . n)'= ( fi. y. n). ( fig . h ) * = 5 (= 3) + 3 ( 4 ) - 0 (fig. d 1.51. dy : - 15 + 12.0 = - 15-3 - 15 * 0 dx