Could you please help me solve the problem?

1. (25 points) The illustration below shows a 4 nC and a -6 nC charge at adjacent corners of an equilateral triangle whose sides are each 7 cm long. There is an X at the third corner. - 1,5 4nc= 4:10 - 60 X sin Q - - 60 10-60_1,50 Gne = - C. 10 6C 60 4:10 -6 6nc. 160 60( 4 nc a. (8 points) Find the electric field at the X (magnitude and direction). If nanc is 10 FE = K 9192 - 9. 109 N/ m 2 2. 4. 10 - 60, 1-61.10 -6 6_ _ 4, 41. 1 2 The is the 2 force between two Not The E- field at That location. b. (6 points) Find the electric potential at the X. UE = 1 9 92 4 . 10 - C . 1 - 61 .10 - 60 YITEO P 4. 3 , 14 . 8 , 8 5 . 10 ( 2/ Nm 2 = g. ( - 4, 83 . 10 - 13 ) = - 4, 40. 10 - 12 2 That's The en between the tu c. (7 points) If we place an electron or a proton at the X, one of them will be repelled from the system and end up very far away. Which? Find its velocity when it is the very far away. - Gnc and - 1,5 will cepel as they have the same charge