Could you please redo the first two questions 1,2,3,4 please and thank you!

1. Calculations using the graphically determined equivalence point volume: a) State the graphically determined equivalence point volume below (and show on graph): 12 20.4 me b) Calculate the concentration of the unknown NaOH or HCI using the graphically determined equivalence point. NH3 (9 ) + HC) (9) - NAY CI (5 ) conc of NeWAS NH3 = 0.1096 volume of NH - 20.4 MC = 0. 0204 1000 n = ( XV = 0.1096 x 0. 0204 = | 2. 24 x 10 - 3 mo 1) Ratio of HCI to NH? is 1:1 2. Calculations using the indicator end point volume: moles ti() : 2.24x10 - 3 mc . /2 a) State the indicator end point volume below (and show on graph): 26.5 ml b) Calculate the concentration of the unknown NaOH or HCI using the indicator end point volume. concentration of M NH 3: 0.1096 volume of NH? = 20. 5ML n = ( X V = 0. 109 6 0. 0705 100 0 = 0+ 0 205 (= 2. 2 4 68 x 10 3 MOD) 3. How does the concentration found using the graphically determined equivalence point compare to the concentration found using the indicator end point? 4. Is the use of an indicator to determine a concentration using titration as good as using a pH meter? Why or why not? 69