Could you solve and explain

20. Given the function f(x) - 2 3x, if we were to find the derivative of f(x) using the definition h-0 h from first principles f'(x) - lim eth)-J(2 what would the first line of our equation look like? A) f' (x) = lim (2-3xth)-(2-3x) h-+0 h B) f'(x) = lim (2-3(xth)) (2-3x) h-+0 h C) f'(x) lim (2-3(xth) ) +(2-32) h D) f' (x) = lim (2-3x+3h)-(2-3x) h-+0 h E) None of the above