Question: CPSC 120 Fall 2017 Lab #5 a-d Instructor: Michael D. Falkow, PMP LAB 5d - Complete Program Step 1: Here is a copy of the

 CPSC 120 Fall 2017 Lab #5 a-d Instructor: Michael D. Falkow,PMP LAB 5d - Complete Program Step 1: Here is a copy

CPSC 120 Fall 2017 Lab #5 a-d Instructor: Michael D. Falkow, PMP LAB 5d - Complete Program Step 1: Here is a copy of the int main) source code vn al // Lab 5d summation,cpp 2 // This program displays a series of terms and computes its sum 3 // PUT YOUR NAME HERE 4 #include 5 #include 6 using namespace std; 7 8 int main() 10 int denom // Denominator of a particular term finalDenom = 64; // Denominator of the final term double sum = 0.0; // Accumulator that adds up all terms in the series 13 14 cout PUT YOUR NAME HERE. n"; 15 16 / WRITE THE CODE TO START A FOR LOOP THAT LOOPS ONCE FOR BACH TERM 17 /I.E., FOR TERMS WITH DENOMINATORS FROM 2 TO THE FINAL DENOMINATOR 2 0 21 // WRITE THE CODE TO PRINT THIS TERM /IF IT IS NOT THE LAST TERM, FOLLOW IT WITH A + /IF IT IS THE LAST TERM, FOLLOW IT WITH A //WRITE THE CODE TO ADD THE VALUE OF THIS TERM TO THE ACCUMULATOR 23 24 25 26 / WRITE A LINE OF CODE TO PRINT THE SUM 27 system("Pause") 28 29 return 0; Design and implement the summation.cpp program so that it generates and prints the terms and the sum of the following series Step 2: 1/2 1/4 1/8 1/16 1/32, 1/64 Sample Run 1/2 1/4 1/81/16 + 1/32 1/64.984375 Modify the program so that it generates and prints the terms and the sum of this series up through the nth term, where the user enters a value for n between 2 and 10. For example, if the user enters 5, the program will display the terms and compute and print the summation of the following terms Step 3: 1/21 + 1/22 1/23 1/24 1/25 This will require the addition of much more program logic as well as some additional variables Sample Run This program sums the series 1/2*1 1/2*2 1/2*3 + What should n be in the final term (2 10)? 5 1/2 + 1/4 + 1/8 + 1/16 + 1/32 0.96875 1/2n Step 4: GET INSTRUCTOR OR LAB ASSISTANT SIGN-OFF (10 POINTs) Page 5 of6

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