create 90% confidence interval for a population proportion from a sample of size 96 with sample proportion

p = 48/96

2.create confidence interval for a population proportion for a point estimate of 0.5 with a margin of error equal to $0.04.

3.Below is a 75% confidence interval for a population proportion from a sample of size 93 with sample proportion

p= 51/93

.

( 0.489 , 0.608 )

Determine the margin of error for this confidence interval.

margin of error =

21Claim: Carzz Magazine claims that the Civic Hybrid gets under 38 mpg on the highway.

A random sample of 10 revealed a mean of 36.57 mpg and a sample standard deviation of 4.94. Use the p-value method at a 10% significance level to test the claim.

=[three decimal accuracy]

p-value =[three decimal accuracy]

conclusion

• Fail to RejectH
• H0
• RejectH0

20.Claim: A Frosted Fruits cereal box contains more than 16 ounces of cereal.

A random sample of 10 revealed a mean of 16.31 ounces and a sample standard deviation of 0.42019. Use the traditional method at a 5% significance level to test the claim.

• Critical Value =[three decimal accuracy]
• Test Statistic =[three decimal accuracy]

conclusion

• Fail to RejectH0
• RejectH0

19.Claim: Carzz Magazine claims that the Civic Hybrid gets less than 38 mpg on the highway. 37 38.1 38.5 36.7 36.8 38 37.9 37.6 38.2 38.1 37.2

Using the sample above, test the claim using the p-value method at a 5% significance level.

=

p-value =

conclusion: Fail to reject Ho or Reject Ho

18.Claim: The average career length for an NFL quarter back is 4.5 years.

A random sample of 10 revealed a mean of 4.93 years and a sample standard deviation of 0.5. Use the traditional method at a 1% significance level to test the claim.

Critical Value =

Test Statistic =

conclusion: Fail to reject HO or Reject Ho

17.Claim: The average rain fall is 4.5 inches.

A random sample of 51 revealed a mean of 4.61 inches. Use the p-value method at a 7% significance level to test the claim assuming a known population standard deviation of 0.59.

=

p-value =

conclsion: Reject Ho or Fail to reject

16.Claim: The average career length for an NFL running back is more than 2.6 years.

A random sample of 47 revealed a mean of 2.65 years. Use the traditional method at a 15% significance level to test the claim assuming a known population standard deviation of 0.23.

Critical Value =

Test Statistic =

conclusion: Reject Ho or fail to reject.

15.Claim: The community pools are exactly 90% full.

A random sample showed that 45 out of 46 pools were 90% full. Use the traditional method at the 5% significance level to test the claim.

Critical z-Score =

Test Statistic =

conclusion: Fail to reject HO or Reject Ho

14.Claim: Less than 75% of adults say that it is morally wrong not to report all income on tax returns.

A random sample showed that 28 out of 45 adults said it was morally wrong. Use the p-value method at the 10% significance level to test the claim.

=

p-value =

conclusion: Reject Ho or fail to reject

13.Claim: A Frosted Fruits cereal box is less than 93% full.

A random sample showed that 45 out of 54 boxes were 93% full or more. Use the traditional method at the 3% significance level to test the claim.

Critical Value =

Test Statistic =

conclusion: Reject HO or fail to reject

12.Determine both critical z-scores corresponding to

= 0.2 in a two-tail test.

3 decimal places.

neg. crititical z-score =

11.The community pools are exactly 90% full.

Select the correct Alternative Hypothesis:

• H_a: 0.90
• H_a: 0.90
• H_a: p 0.90
• H_a: p < 0.90
• H_a: p 0.90
• H_a: > 0.90

9.Create a 95% confidence interval for a population mean from a sample of size 12 with sample meanx= 12.4 and sample standard deviation S = 2.6.

8.Given confidence interval, (23.46, 29.34), determine the point estimate and the margin of error.

3 decimal places

Point Estimate =

7.Determine the positive z-score for a 91% confidence interval.

positive z =

6.Determine the sample size necessary to construct a 90% confidence interval with an error of 2.06 if the population standard deviation is known to be= 12.42.

n=