create a c$++$ program.

Make a program that will read an unknown number of ages. $(0$ is a valid age used for a baby.$)$ The user will

enter a negative number if there are no more ages to enter. The program will output the average age, the

number of minors $($less than $18),$ the number of adults $(18$ and above$)$ and the youngest and oldest ages. If

no ages were entered, display $$No ages were entered$($see the last test case below$).$ You don$$t need to use

fixed $<<$ setprecision$($x$)$ for the average.

Test cases

$[$kslott@empress cs$111\_$lec$\_$spr$11]$$ $./$a$.$out

Enter an age: $20$

Enter an age: $0$

Enter an age: $10$

Enter an age: $5$

Enter an age: $-1$

One space

$8\mathrm{.}75($average$)$

$3($minors$)$

$1($adults$)$

$20($oldest$)$

$0($youngest$)$

$[$kslott@empress cs$111\_$lec$\_$spr$11]$$ $./$a$.$out

Enter an age: $101$

Enter an age: $105$

Enter an age: $-5$

$103($average$)$

$0($minors$)$

$2($adults$)$

$105($oldest$)$

$101($youngest$)$

$[$kslott@empress cs$111\_$lec$\_$spr$11]$$ $./$a$.$out

Enter an age: $10$

Enter an age: $-9$

$10($average$)$

$1($minors$)$

$0($adults$)$

$10($oldest$)$

$10($youngest$)$

$[$kslott@empress cs$111\_$lec$\_$spr$11]$$ $./$a$.$out

Enter an age: $0$

Enter an age: $0$

Enter an age: $-2$

$0($average$)$

$2($minors$)$

$0($adults$)$

$0($oldest$)$

$0($youngest$)$

$[$kslott@empress cs$111\_$lec$\_$spr$11]$$ $./$a$.$out

Enter an age: $-1$

No ages were entered

$[$kslott@empress cs$111\_$lec$\_$spr$11]$$