Create a Junit Test for this to check for typos and or invalid characters... import java.util.Scanner; public class RockPaperScissorsYourLastName { public static int findWinner(String s1,String s2) { int winner = 0; if(s1.equals("rock")) { // if player 1 chooses rock if(s2.equals("rock")) winner = 0; else if(s2.equals("scissors")) winner = 1; else winner = 2; } else if(s1.equals("scissors")) { // if player 1 chooses scissors if(s2.equals("scissors")) winner = 0; else if(s2.equals("paper")) winner = 1; else winner = 2; } else { // if player 1 chooses paper if(s2.equals("paper")) winner = 0; else if(s2.equals("rock")) winner = 1; else winner = 2; } return winner; } public static void main(String[] args){ Scanner pick = new Scanner(System.in); String s1 = ""; //s1 is player 1's choice string String s2 = ""; //s2 is player 2's choice string System.out.println("Player 1: Choose rock, scissors, or paper:"); s1 = pick.next(); s1 = s1.toLowerCase(); System.out.println("Player 2: Choose rock, scissors, or paper:"); s2 = pick.next(); s2 = s2.toLowerCase(); int winner = findWinner(s1,s2); if(winner == 0) { System.out.println("It's a draw! You both chose the same object" + " which is: " + s1 +"."); } else { System.out.println("Player " + winner + " Wins."); } }