Create a package called Q$2.$

$$ Create a java class named IceBreakers that will include the header and footer with your

information that you created in package Q$1.$

$$ Define a public static method called kelvinToFarenheit$(),$ which, when called, will accept

a temperature in degree$-$Kelvin as an argument and return the value in degree$-$Fahrenheit

with the help of the following expression:

$273$

$5$

$=$

$32$

$9,$ where K is in degree$-$Kelvin and f is

in degree$-$Fahrenheit. The method must have the following header, where you need to

decide on the appropriate data types:

public static dataType kelvinToFahrenheit$($dataType kelvin$)$

$$ Define a public static method called fahrenheitToKelvin$(),$ which, when called, will accept

a temperature in degree$-$Fahrenheit as an argument and return the value in degree$-$Kelvin

with the help of the following expression: $273$

$5$

$=$

$32$

$9,$ where K is in degree$-$Kelvin and f is

in degree$-$Fahrenheit. The method must have the following header, where you need to

decide on the appropriate data types:

public static dataType fahrenheitToKelvin $($dataType fahrenheit$)$ Define the driver method $($main$()$ method$)$ with the following specifications:

o Call your public static method myHeader$()$ available in the Q$1.$MyMethods class,

with appropriate arguments. Prior to doing this, on top of the current class

IceBreakers, you need to import the package Q$1.$MyMethods with the statement

import Q$1.$MyMethods; where you defined your static methods myHeader$()$ and

myFooter$().$ This is the advantage of using methods, that will help us cut down

code$-$repetition. You need to call these methods as MyMethods.myHeader$()$ just

like Math.pow$().$ Talk to your instructor if this does not make sense.

o Now mimic the conversation between two individuals in a house, as shown in the

sample output, where the temperature values $($e$.$g$.,-14\mathrm{.}55,18\mathrm{.}5$ and $72$ in the

sample output$)$ will be entered by the user from the keyboard. The tab$-$space in the

sample output can be created with the escape character $\backslash$t$$ within double

quotation $($see unit $2\mathrm{.}3),$ inside any print statement.

o Call myFooter$()$ method with appropriate argumentDefine the driver method $($main$()$ method$)$ with the following specifications:

o Call your public static method myHeader$()$ available in the Q$1.$MyMethods class,

with appropriate arguments. Prior to doing this, on top of the current class

IceBreakers, you need to import the package Q$1.$MyMethods with the statement

import Q$1.$MyMethods; where you defined your static methods myHeader$()$ and

myFooter$().$ This is the advantage of using methods, that will help us cut down

code$-$repetition. You need to call these methods as MyMethods.myHeader$()$ just

like Math.pow$().$ Talk to your instructor if this does not make sense.

o Now mimic the conversation between two individuals in a house, as shown in the

sample output, where the temperature values $($e$.$g$.,-14\mathrm{.}55,18\mathrm{.}5$ and $72$ in the

sample output$)$ will be entered by the user from the keyboard. The tab$-$space in the

sample output can be created with the escape character $\backslash$t$$ within double

quotation $($see unit $2\mathrm{.}3),$ inside any print statement.

o Call myFooter$()$ method with appropriate argument Sample output

$****************************************************$

Full Name: $.......$

Lab Exercise: $3,$ Question: $2$

Program Description: $..........$

$*****************************************************$

What is the outdoor temperature now? $258\mathrm{.}45$

I know you're used to Fahrenheit scale. $258\mathrm{.}45$ deg$-$K is $5\mathrm{.}81$ deg$-$F$.$

I am cold! What is the indoor temperature? $291\mathrm{.}5$

$291\mathrm{.}50$ deg$-$K is $65\mathrm{.}30$ deg$-$F$.$

I see. Would you crank up the temperature?

Ok I will! What temperature should I set the thermostat to$?72$

Oh$,$ you mean $72\mathrm{.}00$ deg Fahrenheit! Here you go$.$

By the way, $72\mathrm{.}00$ deg$-$F is $295\mathrm{.}22$ deg$-$K$.$

Thank you! It is very nice of you.

$***$ Signing off from Question $2$ yourFirstName $***$