Create a purely functional Racket function log2 to approximate log2(x) using the first n terms of the infinite series for ln(x)

lnx = loge (x) = 2[(x-1)/(x+1) +(1/3)((x-1)(x+1))^3 +(1/5)((x-1)(x-1)) +... ]

and

loga(x) = (logb(x))/(logb(a))

Your function should take two parameters, x and the number of terms to compute and it should display an error message if x 0.

I am totally lost! Help please!