Create a python program in that read an integer list that contains set of positive numbers of size "N". The maximum length of element in a list is based on the list size "N". For example if the list size is "6" then the maximum length of each element is "6", Le consider the array elements are [4365, 633, 262645, 48,7,54910](NOTE:Don't read the list elements in the form of strings/charact Create a function called "Recursive_Sum" that takes integer list as argument and calculate the recursive sum for the elements pre the list. For the above example, the first element is 4365, its sum is 4+3+6+5=18->1+8=9 (recursive sum: at last the recursive-su always gets only single digit number it may be any number between 1 and 9), likewise all the elements in the list, the recursive su be calculated. Hence, the newly formed list for the above example is [9,3,7,3,7,1]. Again, Calculate Final Sum (recursive sum) using another fund named "Final_Sum" for the elements currently present in the newly formed list. ie. 9+3+7+3+7+1=30->3+0=3. After finding out the "Final_Sum", in this case it is 3, now check whether the Final Sum (ie. 3) is exist in the each item in the input the Final Sum (ie. 3) is present then replace the element with 1 otherwise O. Hence our input list now becomes (1,1,0,0,0,0). Well-done, but your job is not yet over, convert this binary number [110000) to equivalent decimal number. ie. here it is 48. Yes, final result. ALL THE BEST. Input: 6 //array size 4365 633 262645 48 7 54910 Output 48