create a vector called unemploy$\_$rate with $12$ values, one for each month in $2013.$ The values for each month are listed below $($beginning with January$$s rate of $7\mathrm{.}9)$

$7\mathrm{.}97\mathrm{.}77\mathrm{.}57\mathrm{.}57\mathrm{.}57\mathrm{.}57\mathrm{.}37\mathrm{.}27\mathrm{.}27\mathrm{.}27\mathrm{.}06\mathrm{.}7$